When a bomb explodes into two pieces, they move in opposite directions. This motion in opposite direction can be explained by

Law of conservation of energy

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Law of conservation of momentum

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Law of conservation of mass

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Law of conservation of charge

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Solution

The correct option is D Law of conservation of momentum

As initial momentum of bond $= 0$ ( $∵$ $V = 0$ )
So, to keep final momentum $= 0$
small exploded masses go in opposite direction to notify the effect.
i.e, $M_{1} V_{1} = M_{2} V_{2}$
$P_{t} = M_{2} V_{2} - M_{1} V_{1} = 0$

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When a bomb explodes into two pieces, they move in opposite directions. This motion in opposite direction can be explained by

The correct option is D Law of conservation of momentumAs initial momentum of bond =0 (∵ V=0)So, to keep final momentum =0small exploded masses go in opposite direction to notify the effect.i.e, M1V1=M2V2Pt=M2V2−M1V1=0

The correct option is D Law of conservation of momentum

As initial momentum of bond $= 0$ ( $∵$ $V = 0$ )
So, to keep final momentum $= 0$
small exploded masses go in opposite direction to notify the effect.
i.e, $M_{1} V_{1} = M_{2} V_{2}$
$P_{t} = M_{2} V_{2} - M_{1} V_{1} = 0$