When a boy weighing 20 kgf sits at one end of a 4 m long see-saw, it gets depressed at this end. How can it be brought to the horizontal position by a man weighing 40 kgf.

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Solution

From the principle of moments, $20 k g f \times 4 m = 40 k g f \times L$

$\Rightarrow L = 2 m$

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When a boy weighing 20 kg sits at one end of a 4 m long see-saw, it gets depressed at this end. How can it be brought to the horizontal position by an another boy weighing 40 kg?

When a boy weighing $20 k g$ sits at one end of a $4 m$ long see-saw, it gets depressed at this end. How can it be brought to the horizontal position by another boy weighing $40 k g$ ?