When a capacitor of capacitance C is filled with a dielectric (i.e. thickness of the dielectric is equal to the spacing between the plates) of dielectric constant k, what is the new capacitance?

C k

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\frac{C}{k}

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C k^{2}

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\frac{C}{k^{2}}

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Solution

The correct option is A $C k$
When t=d for the dielectric introduced,
The formula for new capacitance,
$C^{'} = \frac{ε_{0} A}{d - t + \frac{t}{k}}$
It changes to,
$C^{'} = \frac{k ε_{0} A}{t}$
Since t=d,
C'=kC

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When a capacitor of capacitance C is filled with a dielectric (i.e. thickness of the dielectric is equal to the spacing between the plates) of dielectric constant k, what is the new capacitance?

The correct option is A CkWhen t=d for the dielectric introduced, The formula for new capacitance, C′=ε0Ad−t+tk It changes to, C′=kε0At Since t=d, C'=kC

The correct option is A $C k$
When t=d for the dielectric introduced,
The formula for new capacitance,
$C^{'} = \frac{ε_{0} A}{d - t + \frac{t}{k}}$
It changes to,
$C^{'} = \frac{k ε_{0} A}{t}$
Since t=d,
C'=kC