When a capillary tube is dipped in a liquid, liquid rises 0.06m in it. Surface tension of liquid is 0.03N/m, density of liquid is 103kg/m3. If contact angle is 60∘, then radius of capillary is (Assume g=10m/s2)
A
1mm
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B
0.5mm
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C
0.05mm
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D
0.01mm
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Solution
The correct option is C0.05mm Given: h=0.06m,θ=60∘ T=0.03N/m,ρ=103kg/m3 g=10m/s2 We know that, h=2Tcosθrρg ⇒r=2Tcosθhρg=2×0.03×cos60∘0.06×103×10⇒r=0.05mm