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Byju's Answer
Standard XII
Physics
3rd Equation of Motion
When a car dr...
Question
When a car driver travelling at a speed of 10 m/s applies brakes and brings the car to rest in 20 s, then retardation will be:
(a) + 2 m/s
2
(b) − 2 m/s
2
(c) − 0.5 m/s
2
(d) + 0.5 m/s
2
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Solution
(d) The term “retardation” means negative acceleration.
Initial velocity = 10 m/s
Final velocity = 0 m/s
Time taken = 20 s
Acceleration
=
0
-
10
20
⇒
Acceleration
=
-
0
.
5
m
/
s
2
⇒
Retardation
=
0
.
5
m
/
s
2
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