Question

When a certain amount of ethylene was combusted, 6226 kJ heat was evolved. If heat of combustion of ethyleneis 1411 kJ, Determinethe volume of $O_2$ (at NTP) that entered into the reaction

• A. 996.3 L
• B. 234 L
• C. 296 L
• D. 435 L

Answer 1

The correct option is C 296 L

$C_2{H}_4+3O_2\to 2C{O}_2+2H_{2}O\Delta H=-6226kJ$

moles of $O_2$ are used in the reaction $=\frac{6226\times 3}{1411}$

Volume of $O_2$ entered in the reaction$=\frac{6226\times 3\times 22.4}{1411}=296.5l$