When a certain force is applied on a string it extends by 0.01cm. When the same force is applied on another string of same material, twice the length and double the diameter, then the extension in second string is
A
0.005 cm
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B
0.02 cm
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C
0.08 cm
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D
0.04 cm
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Solution
The correct option is A 0.005 cm
△l=Flπ(d2)2Y
0.01=Flπ(d2)2Y
△l1=F2lπ4(d2)2Y
=12Flπ(d2)2Y (also take the ratio in the next step)