When a certain length of wire is turned into one circular loop. tire magnetic induction at the centre of coil due to some current flowing is $B_{1}$ , If the same wire is turned into three loops to make a circular coil. the magnetic induction at the center of this coil for the same current will be

B_{1}

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{9 B}_{1}

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{3 B}_{1}

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{27 B}_{1}

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Solution

The correct option is C ${9 B}_{1}$
The magnetic field at the center of loop is given as:
$B = n^{2} B_{0}$
where $n$ is number of loops
here n = 3

So, $B = (3)^{2} B_{1}$
$= 9 B_{1}$

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When a certain length of wire is turned into one circular loop. tire magnetic induction at the centre of coil due to some current flowing is B1, If the same wire is turned into three loops to make a circular coil. the magnetic induction at the center of this coil for the same current will be

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The correct option is C ${9 B}_{1}$
The magnetic field at the center of loop is given as:
$B = n^{2} B_{0}$
where $n$ is number of loops
here n = 3

So, $B = (3)^{2} B_{1}$
$= 9 B_{1}$