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Question

When a certain metal was irradiated with light of frequency 1.6 × 1016 Hz, the photoelectrons emitted had twice the kinetic energy as the photoelectrons emitted when the same metal was irradiated with light of frequency 1.0 × 1016 Hz. Calculate the threshold frequency (v0) for the metal.


A

2 × 1015 Hz

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B

6 × 1015 Hz

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C

12 × 1015 Hz

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D

4 × 1015 Hz

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Solution

The correct option is D

4 × 1015 Hz


From Einstein's equation, we know

KE = hν - hν0

KE2 = KE12

Now, KE1 = h(ν ν0)

KE2 = h(ν2 ν0)

ν2 ν0ν1 ν0 = 12

1 × 1016 ν01.6 × 1016 ν0 = 12

Thethresholdfrequency ν0 = 4 × 1015 Hz


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