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Sulphuric Acid

When a colour...

Question

When a colourless gas is passed through bromine water, decolourization takes place. The gas is:

S O_{2}

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H B r

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H C l

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H_{2} S

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Solution

The correct option is B $S O_{2}$
When sulphur dioxide gas is passed through bromine water, the water turns from red to colourless. This is because of the reducing property of sulphur dioxide that reduces the coloured solution to halides, making them colourless.

$S O_{2} + B r_{2} + 2 H_{2} O \to 2 H B r + H_{2} S O_{4}$

Hence, option A is correct.

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