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Question

When a conducting wire is connected in the right gap and a known resistance in the left gap, the balancing length is 60cm. If the wire is stretched so that its length increases by 20%, then the balancing length becomes
  1. 54 cm
  2. 65.6 cm
  3. 64 cm
  4. 51 cm


Solution

The correct option is D 51 cm
R1R2=6040=32(1)R1R12=l1100l1(2)R12R2=[l12l2]2=[120100]2=1.44FromEq(2)R11.44R2=l1100l131.44×2=l1100l132.88=l1100l13003l1=2.88l1300=5.88l1l1=3005.88=51 cm

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