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Question
When a current changes from + 2A to – 2A in 0.05s, an emf of 8V induced in a coil. The coefficient of self induction of coil is:
When a current changes from + 2A to – 2A in 0.05s, an emf of 8V induced in a coil. The coefficient of self induction of coil is:
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Solution
The correct option is C 0.1H
E=−Ldidt=−2[i2−i1t]
8=−L[−2−20.05]
L=0.1 H
E=−Ldidt=−2[i2−i1t]
8=−L[−2−20.05]
L=0.1 H
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