When a current of $100 mA$ is passed through a galvanometer, it gives a full deflection of $100$ divisions . If resistance of galvanometer is $500 Ω$ , calculate its voltage semitivity.

4 div/V

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2 div/V

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1 div/V

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0.2 div/V

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Solution

The correct option is B $2 div/V$
Full deflection voltage is given by, $V_{g} = I_{g} . G$

$∴ V_{g} = (100 \times 10^{- 3}) \times 500 = 50 V$

Voltage senritivity, $V_{s} = \frac{θ_{m a x}}{V_{g}}$

$V_{s} = \frac{100}{50} = 2 div/V$

Hence, option $(B)$ is the correct answer.

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When a current of 100 mA is passed through a galvanometer, it gives a full deflection of 100 divisions . If resistance of galvanometer is 500 Ω, calculate its voltage semitivity.

The correct option is B 2 div/VFull deflection voltage is given by, Vg=Ig.G ∴Vg=(100×10−3)×500=50 V Voltage senritivity, Vs=θmaxVg Vs=10050=2 div/V Hence, option (B) is the correct answer.

When a current of $100 mA$ is passed through a galvanometer, it gives a full deflection of $100$ divisions . If resistance of galvanometer is $500 Ω$ , calculate its voltage semitivity.

The correct option is B $2 div/V$
Full deflection voltage is given by, $V_{g} = I_{g} . G$

$∴ V_{g} = (100 \times 10^{- 3}) \times 500 = 50 V$

Voltage senritivity, $V_{s} = \frac{θ_{m a x}}{V_{g}}$

$V_{s} = \frac{100}{50} = 2 div/V$

Hence, option $(B)$ is the correct answer.