Question

When a current of 2 A is passed through a coil of 100 turns, flux associated with it is $5\times {10}^{-5}$ Wb.
Find the self inductance of the coil.

• A. $4\times {10}^{-3}H$
• B. $4\times {10}^{-2}H$
• C. $2.5\times {10}^{-3}H$
• D. ${10}^{-3}H$

Answer 1

The correct option is C $2.5\times {10}^{-3}H$

Total flux passing through a coil=$N\varphi =Li$

where $L$ is the self inductance of coil.

$⟹L=\frac{N\varphi }{i}=\frac{100\times 5\times {10}^{-5}}{2}$

$=2.5\times {10}^{-3}H$