Question

When a dice is thrown, find the probability that either an odd number or a multiple of $4$ occurs

Answer 1

Sample space of total number of outcomes = {1, 2, 3, 4, 5, 6}

Number of total outcomes = 6

Odd number = {1, 3, 5} =3

Multiple of 4 = {4} = 1

Hence the favorable number of outcomes for a number to be either an odd number or a multiple of 4 = 3+1=4

Therefore the probability that either an odd number or a multiple of 4 occurs = $\frac{\text{Favourable outcomes}}{\text{Total number of outcomes}}=\frac{4}{6}=\frac{2}{3}$