When a dielectric slab is introduced between the plates of a charged parallel plate capacitor, its :

Potential increases

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Electric field decreases

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Charge increases

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Capacitance decreases

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Solution

The correct option is C Electric field decreases
When a dielectric is placed between charged plates, the polarization of the medium produces an electric field opposing the field of the charges on the plate. The dielectric constant $K$ is defined to reflect the amount of reduction of effective electric field.

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