When a fast moving vehicle is suddenly stopped by force of $200 N$ , it came to rest after travelling $1 m$ . The magnitude of work done by the force is $200 J$ .

Due to opposing force of friction

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Solution

The correct option is A
Due to opposing force of friction

Given:
Force, $F = 200 N$
Displacement, $s = 1 m$

Work done $(W)$ is the product of displacement and the force acting along the displacement. Its magnitude is given by:
$| W | = F s$
$| W | = 200 \times 1 = 200 J$

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When a fast moving vehicle is suddenly stopped by force of 200N, it came to rest after travelling 1m. The magnitude of work done by the force is 200J.

The correct option is A Due to opposing force of friction Given: Force, F=200N Displacement, s=1m Work done (W) is the product of displacement and the force acting along the displacement. Its magnitude is given by: |W|=Fs |W|=200×1=200J

When a fast moving vehicle is suddenly stopped by force of $200 N$ , it came to rest after travelling $1 m$ . The magnitude of work done by the force is $200 J$ .

The correct option is A
Due to opposing force of friction

Given:
Force, $F = 200 N$
Displacement, $s = 1 m$

Work done $(W)$ is the product of displacement and the force acting along the displacement. Its magnitude is given by:
$| W | = F s$
$| W | = 200 \times 1 = 200 J$