When a force vector F-2-k- N acts on a body and produces a displacement of S-4-7k- m- then the work done in J is

The correct option is C 13Work = F.s #160; #160; #160; #160; #160; #160; = 4+2+7 = 13 J ...

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Vector Addition

When a force ...

Question

When a force vector $¯ ¯¯ ¯ F = (^i + 2^j +^k) N$ acts on a body and produces a displacement of $¯ ¯ ¯ S = (4^i +^j + 7^k) m$ , then the work done (in J) is

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Solution

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\to F = (^i - 2^j +^k) N

(0, 1, 1) m

(0, - 2, 3) m

\to F = 3^i + c^j + 2^k

\to S = - 4^i + 2^j - 3^k

6 J

c

\to F = (^i + 2^j + 3^k) N

r_{1} = (^i +^j +^k)

r_{2} = (^i -^j + 2^k)

\to F = (^i + 2^j + 3^k) N

r_{1} = (^i +^j +^k)

r_{2} = (^i -^j + 2^k)

F = (^i + 2^j + 3^k) N

_{1} =^i +^j +^k

_{2} =^i -^j + 2^k

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