Question

When a graph is plotted between $log\frac{x}{m}$ and $logp$, it is a straight line with an angle ${45}^o$ and intercept 0.3010 on y-axis. If the pressure is $0.3atm$, what will be the amount of gas adsorbed per $gm$ of adsorbent:

• A. 0.4
• B. 0.6
• C. 0.8
• D. 0.1

Answer 1

Answer: (B)

0.6

$log\frac{x,}{m}=logK+\frac{1}{n}logP$
$\Rightarrow \frac{1}{n}=tan{45}^0\Rightarrow n=1$
$\to logK=\mathrm{0.0.3010},K=2$
$\Rightarrow \frac{x}{m}=2\times (0.3{)}^1\Rightarrow x=0.6$