Question

When a graph is plotted between $\log x/m$ and log p, it is a straight line with an angle ${45}^o$ and intercept $0.3010$ on y-axis. If the initial pressure is $0.3$ atm, what will be the amount of gas adsorbed per gram of the adsorbent?

• A. $0.4$
• B. $0.6$
• C. $0.8$
• D. $0.1$

Answer 1

The correct option is B $0.6$

log$\frac{x}{m}=logk+\frac{1}{n}$log$P$

Given,

$\frac{1}{n}=tan{45}^0$ and $logk=0.3010$

Hence, $n=1$ and $k=2$.

$\frac{x}{m}=k\times P^1$

Therefore, $\frac{x}{m}=2\times (0.3{)}^1$.

or $x=0.6$.