Question

When a heterozygous bald man marries a heterozygous non bald woman, the probability of bald and non sons.

• A. $3:1$
• B. $1:3$
• C. $1:1$
• D. $2:1$

Answer 1

The correct option is A $3:1$

As the blad gene is heterozygous in make so there are 100% chances of a son with blad and no blad gene to daughter.

So the correct option is '3:1’.