Question

When a hydrogen atom is raised from the ground state to and excited state

• A. P.E increases and K.E decreases
• B. P.E decreases and K.E increases
• C. Both energy (K.E and P.E) increases
• D. Both K.E and P.E decreases

Answer 1

The correct option is A P.E increases and K.E decreases

In excited state, r increases,
$K.E.=\frac{Z{e}^2}{2r}$ decreases
$P.E.=-\frac{Z{e}^2}{r}$, becomes less negative i.e more positive.