Question

When a hydrogen sample in the ground state is bombarded then what potential is required to accelerate electron so that first Paschen line is emitted, then calculate the energy difference?

• A. $2.55$
• B. $0.65$
• C. $12.09$
• D. $12.75$

Answer 1

The correct option is D $12.75$

In H-atom, the energy of ground state=$-13.6ev$

Energy of paschen state=$-1.51ev$

Energy of third excited state=$-0.85ev$

Hence the difference between the ground state and third excited state.

= 3rd excited state - ground state

=$\left(-0.85-\left(-13.6\right)\right)ev$

=$12.75ev$

So, the correct option is $D$