Question

When a jet plane flying at 300 m/s along a circle in vertical plane, it is observed that at the top of its trajectory, the apparent weight of a passenger is one half of her actual weight. Find the radius of curvature R of the flight path at this point. Use g = 10 m/s${}^2$

• A. 22 km
• B. 18 km
• C. 30 km
• D. 16 km

Answer 1

The correct option is B 18 km

Apparent weight $=mg-mr{\omega }^2=\frac{mg}{2}$

$\therefore r=\frac{2v^2}{g}(\omega =\frac{v}{r})$

$=\frac{2\times (300{)}^2}{10}=18km$