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Lead Ion

When a KI sol...

Question

When a KI solution was added to a solution of mercury (II) chloride, a precipitate mercury (II) iodide formed. A student plotted the mass of the precipitate versus the volume of the KI solution added and obtained the above graph.
Based on the above graph, the species formed after maximum is attained is called___________.

A

Nessler's reagent

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B

Tollen's reagent

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C

Iodide of Millon's base

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D

None of the above is correct

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Solution

The correct option is A Nessler's reagent
$H g C l_{2}$ reacts with KI to form $H g I_{2}$ .

$H g C l_{2} + 2 K I \to H g I_{2} + 2 K C l$

As the reaction proceeds, more and more of $H g I_{2}$ is obtained until a maximum value is reached.
Then the mass of $H g I_{2}$ decreases due to formation of $K_{2} H g I_{4}$ .

$H g I_{2} + 2 K I \to K_{2} H g I_{4}$

Species formed after maximum is attained is called Nessler's reagent.
Nessler's reagent is used to idntify $N H_{4}^{+}$ ions.

$2 K_{2} H g I_{4} + 4 K O H + N H_{4} C l \to H g_{2} N H_{2} O I b r o w n p r e c i p i t a t e + 7 K I + K C l + 3 H_{2} O$

Therefore, option A is correct.

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