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Question

When a KI solution was added to a solution of mercury (II) chloride, a precipitate mercury (II) iodide formed. A student plotted the mass of the precipitate versus the volume of the KI solution added and obtained the above graph.

As KI is added to HgCl2 solution, there is increase in the mass of HgI2 but after a maximum point is reached, mass of HgI2 decreases. It is due to__________.
205573_37978f5b39b64a5db528a25101d59f6c.png

A
Formation of soluble K3HgI5
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B
Formation of soluble K2HgI4
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C
Decomposition of HgI2 into Hg2I2 and I2
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D
Decomposition of HgI2 into Hg and I2
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Solution

The correct option is B Formation of soluble K2HgI4
HgCl2 reacts with KI to form HgI2.

HgCl2+2KIHgI2+2KCl.

As the reaction proceeds, more and more of HgI2 is obtained until a maximum value is reached.

Then the mass of HgI2 decreases due to formation of K2HgI4.

HgI2+2KIK2HgI4

Therefore, option B is correct.


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