Question

# When a ling spring is stretched by $$2cm$$ its potential energy is $$U$$. If the spring is stretched by $$10cm$$, the potential energy stored in it will be

A
25U
B
U5
C
5U
D
10U

Solution

## The correct option is A $$25U$$$$\dfrac{PE_1}{PE_2 }=\dfrac{x_1^2}{x_2^2}=\dfrac{2^2 }{10^2}=\dfrac{1}{25}$$$$\Rightarrow PE_2=25\times PE_1 =25U$$Hence correct answer is option $$A$$ Physics

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