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Question

When a ling spring is stretched by $$2cm$$ its potential energy is $$U$$. If the spring is stretched by $$10cm$$, the potential energy stored in it will be


A
25U
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B
U5
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C
5U
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D
10U
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Solution

The correct option is A $$25U$$

$$\dfrac{PE_1}{PE_2 }=\dfrac{x_1^2}{x_2^2}=\dfrac{2^2 }{10^2}=\dfrac{1}{25} $$
$$\Rightarrow PE_2=25\times PE_1 =25U$$

Hence correct answer is option $$A $$ 

Physics

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