When a liquid X is cooled at 0 $°$ C, it gets converted into solid state by a process called 'A'. When the liquid is heated at 100 $°$ C, it gets converted into gaseous state by a process called 'B'. Identify X, A and B.

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Solution

When a liquid X is cooled at 0 $°$ C, it gets converted into a solid-state by a process called 'A'.
$X \to_{A}^{0 ° C} SOLID$
Here the liquid X on providing a temperature of 0 $°$ C changes to solid by the process called freezing(A).
Freezing is the process of changing a liquid to a solid by cooling.
Freezing point of water is 0 $°$ C
Here ‘A’ is freezing.
When the liquid is heated at 100 $°$ C, it gets converted into a gaseous state by a process called 'B'.
$X \to_{B}^{100 ° C} Gaseous$
Here the liquid X on providing a temperature of 100 $°$ C changes to solid by the process called Boiling(B).
Boiling is the process in which a liquid substance changes to gas on heating.
Boiling point of water is 100 $°$ C
Here ‘B’ is boiling.
Now liquid X undergoes freezing at 0 $°$ C and boiling at 100 $°$ C so this liquid is water.
Conclusion:
A - Freezing
B - Boiling
X - Water

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When a liquid X is cooled at 0°C, it gets converted into solid state by a process called 'A'. When the liquid is heated at 100°C, it gets converted into gaseous state by a process called 'B'. Identify X, A and B.

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