Question

When a load of $10$ kg is suspended on wire, its length increase by $2$ mm. constant of the wire is.

Answer 1

$mass=10kg$

Increase in length = $2mm$ .

Force constant , k = ?

We know the formula ,

$F=k(L_2-L_1)$

$mg=k(L_2-L_{!})$
$k=\frac{(10\times 9.8)}{2\times {10}^{-3}}$

$k=\frac{98}{2\times {10}^{-3}}$

$k=49000N{m}^{-1}$