When a mass m is hung from the lower of a spring of negligible mass, an extension x is produced in the spring. The mass is set into vertical oscillations.The time period of oscillation is

T = 2 π \sqrt{\frac{x}{m g}}

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T = 2 π \sqrt{\frac{g x}{m}}

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T = 2 π \sqrt{\frac{x}{g}}

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T = 2 π \sqrt{\frac{x}{2 g}}

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Solution

The correct option is C $T = 2 π \sqrt{\frac{x}{g}}$
If k is the force constant, we have
mg=kx
or $\frac{m}{k} = \frac{x}{g}$
$∴ T = 2 π \sqrt{\frac{m}{k}} = 2 π \sqrt{\frac{x}{g}}$

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When a mass m is hung from the lower of a spring of negligible mass, an extension x is produced in the spring. The mass is set into vertical oscillations.The time period of oscillation is

The correct option is C T=2π√xgIf k is the force constant, we have mg=kx or mk=xg ∴T=2π√mk=2π√xg

The correct option is C $T = 2 π \sqrt{\frac{x}{g}}$
If k is the force constant, we have
mg=kx
or $\frac{m}{k} = \frac{x}{g}$
$∴ T = 2 π \sqrt{\frac{m}{k}} = 2 π \sqrt{\frac{x}{g}}$