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Compressibility

When a metal ...

Question

When a metal ball is immersed in a liquid, the apparent weight of the ball at $0^{o} C$ and $50^{o} C$ are found to be $W_{1}$ and $W_{2}$ respectively. If $γ_{s} < γ_{l}$

W_{1} > W_{2}

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W_{1} = W_{2}

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W_{2} > W_{1}

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Solution

The correct option is C $W_{2} > W_{1}$
Given,

$γ_{s} < γ_{L}$

The coefficient of expansion of solid is less than the coefficient of expansion of the liquid.

Because of this, the weight of displaced liquid will decrease as temperature increase. Therefore buoyancy force decrease

Hence, the apparent weight will increase as the temperature increase, $W_{1} < W_{2}$

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When a metal ball is immersed in a liquid, the apparent weight of the ball at 0oC and 50oC are found to be W1 and W2 respectively. If γs<γl

When a metal ball is immersed in a liquid, the apparent weight of the ball at $0^{o} C$ and $50^{o} C$ are found to be $W_{1}$ and $W_{2}$ respectively. If $γ_{s} < γ_{l}$