Question

When a metal burnt its weight is inccreased by $24$%, the equivalent weight of metal is:-

Answer 1

The equivalent weight of oxide = $\frac{\text{molar mass of oxygen}}{\text{charge on oxygen}}$

=$\frac{16mo{l}^{-1}}{8gmolee{q}^{-1}}=8ge{q}^{-1}$

One equivalent of the metal reacts with one equivalent of oxygen to form a metal oxide.

Let us consider M to be the equivalent weight of the metal.

Therefore, when M grams of the metal will react with 8g of oxygen the corresponding metal oxide formed will be 8gm more in Mass. This 8 gram is 24% of M.

M $=\frac{100\times 8}{24}$

$=\frac{100}{3}$

$=33.3g$