When a metallic oxide is dissolved in water, the solution formed has a high concentration of _______. ions. $(H^{+}, H_{3} O^{+}, O H^{-})$ .

Open in App

Solution

When a metallic oxide is dissolved in water, the solution formed has a high concentration of hydroxide ( $O H^{-}$ ) ions. Such solutions are basic in nature. For example, when sodium oxide is dissolved in water, it forms sodium hydroxide.
$N a_{2} O + H_{2} O \to 2 N a O H$
Sodium hydroxide dissociates in water to provide hydroxide ions.
$N a O H \to N a^{+} + O H^{-}$

Suggest Corrections

Similar questions

^{-}

"Mixing an acid or base with water results in decrease in the concentration of ions(H3O/OH-) per unit volume"

Acid when mixed with water gives out H+ ions which because they cannot exist alone form H3O ions. Then how does the concentration 'decrease' ?

({OH}^{-})

O H^{-}

How a base when dissolved in water furnish both H+ & OH- ions?

Join BYJU'S Learning Program