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Question

When a metallic wire is stretched with a tension T1 its length is l1 and with a tension T2 its length is l2. The original length of the wire is:

A
l1T2l2T1T2T1
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B
l1T2+l2T1T2+T1
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C
l1l2
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D
l1l22
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Solution

The correct option is A l1T2l2T1T2T1
From the relation between stress and strain, we get,

FA=YΔll

Thus T1A=Yl1ll and T2A=Yl2ll

Dividing the two equations, we get,

T1T2=ll1ll2

l=l1T2l2T1T2T1



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