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Chemical Reactions

When a minera...

Question

When a mineral (A) is boiled with $N a_{2} C O_{3}$ . A white precipitate (B) is formed. The precipitate is filtered and $C O_{2}$ is passed through the filtrate, then a compound (C) sparingly soluble in cold water is formed. The compound (C) on strong heating gave two compounds D and E on heating with cobalt oxide produces blue coloured substance (F). Identify A to F and give balanced chemical reactions

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Solution

Let consider the reaction in acidic medium
$(A) = C a (O H)_{2}$
$(B) = C a C O_{3}$ (white ppt)
$(C) = C a H C O_{3}$
$(D) = C a O$
$(E) = C O_{2}$
In acidic medium.
$N a_{2} C O_{3} \to 2 N a^{+} + C O_{3}^{2 -}$
$C O_{3}^{2 -} + H^{+} \to C O_{2} ↑$
$C O_{2} + C a (O H)_{2} \to C a C O_{3}$
$C O_{2} + B a (O H)_{2} \to B a C O_{3}$ } white
$C a C O_{3} / B a C O_{3} + H_{2} O + C O_{2} \to C a (H C O_{3})_{2} / B a (H C O_{3})_{2}$
on strong heating
$C a (H C O_{3}) / B a (H C O_{3}) Δ \to C a O + C O_{2}$

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