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Limiting Reagent or Reactant

When a mixtur...

Question

When a mixture containing $10$ moles of $S O_{2}$ and $15$ moles of $O_{2}$ is passed over catalyst, $8$ moles of $S O_{3}$ is formed. How many moles of $S O_{2}$ and $O_{2}$ did not enter into combination respectively?

A

2, 11

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B

4, 22

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C

11, 2

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D

22, 4

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Solution

The correct option is A $2, 11$
$2 S O_{2} + O_{2} ⇌ 2 S O_{3}$
2 moles of $S O_{2}$ will react with 1 mole of $O_{2}$ to form 4 moles of $S O_{3}$ .
8 moles of $S O_{2}$ will react with 4 moles of $O_{2}$ to form 8 moles of $S O_{3}$ .
Hence, $10 - 8 = 2$ moles of $S O_{2}$ and $15 - 4 = 11$ moles of $O_{2}$ did not enter into the combination respectively.

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Similar questions

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