wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

When a mixture containing 10 moles of SO2 and 15 moles of O2 is passed over catalyst, 8 moles of SO3 is formed. How many moles of SO2 and O2 did not enter into combination respectively?

A
2, 11
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
4, 22
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
11, 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
22, 4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2, 11
2SO2+O22SO3
2 moles of SO2 will react with 1 mole of O2 to form 4 moles of SO3.
8 moles of SO2 will react with 4 moles of O2 to form 8 moles of SO3.
Hence, 108=2 moles of SO2 and 154=11 moles of O2 did not enter into the combination respectively.

flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Limiting Reagent
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon