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Stoichiometric Calculations

When a mixtur...

Question

When a mixture of 10 moles of $S O_{2}$ and 16 moles of $O_{2}$ were passed over a catalyst, 8 moles of $S O_{3}$ were formed at equilibrium. The number of moles of $S O_{2}$ and $O_{2}$ remaining unreacted were:

A

2, 12

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B

12, 2

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C

3, 10

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D

10, 3

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Solution

The correct option is A 2, 12
$2 S O_{2} (g) + O_{2} ⇌ 2 S O_{3} (g)$
t=0 10 16 0
$t_{e q}$ (10-2x) (16-x) 2x
2x=8, i.e., x=4
$∴$ Remaining $S O_{2} = 10 - 8 = 2 m o l$
Remaining $O_{2} = 16 - 4 = 12 m o l$

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