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Question

When a mixture of NaBr and NaCl is repeatedly digested with H2SO4, all the halogens are expelled and Na2SO4 is formed quantitatively. With a particular mixture, it was found that the mass of Na2SO4 obtained is precisely the same as the mass of NaBr and NaCl mixture taken. The mass ratio of NaCl and NaBr in the mixture is (as nearest integer only) :

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Solution

NaBrH2SO4−−−Na2SO4
a g
NaClH2SO4−−−Na2SO4
b g
Meq. of NaBr+ Meq. of NaCl = Meq. of Na2SO4
Meq. of Na2SO4 formed =a103×1000+b58.5×1000 =9.71a+17.09b
w1422×1000=9.71a+17.09
w=1422000[9.71a+17.09b]
Also,
mass of NaCl + mass of NaBr = mass of Na2SO4 formed
a+b=1422000[9.71a+17.09b]

ab=426.78621.18=0.687

Ratio of NaClNaBr =ba=1.4551
So, the ratio as nearest integer is 1.

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