We know,
Boiling point elevation constant,
Kb=RT2b1000 Lv
where,
Tb is boiling point of pure solvent in K
R in cal/mol/K
Lv is latent heat of vaourisation of solvent in cal/g
Thus,
Kb=2×(46.30+273)21000×84=2.43
Boiling point elevation of a solution is given by,
△Tb=Kb×m
∴ m=△TbKb=0.552.43
And also, m=moles of solutewt. of solvent in grams×1000
=10M×1000150=2003M
where, M is the molar weight of the non-volatile solute.
Thus, 2003M=0.552.43; M=294.5 g/mol
Thus, the molar mass of non-volatile solute is 294.5 g/mol