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Question

When a particle executing SHM oscillates with a frequency ω , then the kinetic energy of the particle

A
Changes periodically with a frequency of ω
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B
Changes periodically with a frequency of 2ω
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C
Changes periodically with a frequency of ω2
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D
Remains constant
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Solution

The correct option is B Changes periodically with a frequency of 2ω
When the frequency of the SHM is ω, the motion is represented as x=Asinωt.
Hence the kinetic energy of the motion is given as
K=12mv2
=12m(Aωcos(ωt))2
=12mA2ω2cos2(ωt)
=12mA2ω2(cos2ωt+12)
which has frequency of 2ω.

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