Question

When a particle is thrown vertically upwards, its velocity at one fourth of its maximum height is $10\sqrt{5}$m/s. The maximum height attained by it is:

• A. 33.3 m
• B. 25 m
• C. 50 m
• D. 44.4 m

Answer 1

The correct option is B 25 m

Given:
Velocity at $h_{max}=10\sqrt{5}$m/s

Now, in upward direction, a=-g, v=0.

$h=\frac{v^2}{2g}$

$h=\frac{(10\sqrt{5}{)}^2}{2\times 10}$

$h=\frac{100\times 5}{20}$=25 m