When a particle oscillates simple harmonically,its kinetic energies varies periodically.if frequency of the particle is f,the frequency of the kinetic energy is :
A)f/2 B)f C)2f D)4f
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Solution
So we have to find the frequency of K.E. Okay! Let's take the mean position as reference and try to figure out. When the particle crosses the mean position its K.E is maximum and P.E is zero so basically K.E. = T.E at this position. Lets say at t=0 the particle crosses the mean position its K.E. = Kmax. It would come back to mean position after time T2 and have the same magnitude of velocity and hence same K.E. = Kmax since K.E. "repeats” itself in half the time period of SHM its frequency will be twice i.e., 2f.