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Question

When a photon of frequency v hits the surface of a metal with a threshold frequency v0 (v>v0) then which of the following options is correct about the ejected photoelectron?

A
wavelength is cv
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B
wavelength is cvv0
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C
wavelength is proportional to (vv0)
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D
square of the wavelength is inversely proportional to (vv0)
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Solution

The correct option is D square of the wavelength is inversely proportional to (vv0)
Energy of ejected electron:
hv=hv0+K.E.
K.E.=h(vv0)
where v0 is threshold frequency.
Using de-Broglie equation, wavelength of photoelectron is given by
λ=h2m×K.E.
λ=h2m×h(vv0)

λ2=h2m(vv0)

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