When a photon of frequency v hits the surface of a metal with a threshold frequency v0(v>v0) then which of the following options is correct about the ejected photoelectron?
A
wavelength is cv
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B
wavelength is cv−v0
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C
wavelength is proportional to (v−v0)
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D
square of the wavelength is inversely proportional to (v−v0)
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Solution
The correct option is D square of the wavelength is inversely proportional to (v−v0) Energy of ejected electron: hv=hv0+K.E. ⇒K.E.=h(v−v0) where v0 is threshold frequency. Using de-Broglie equation, wavelength of photoelectron is given by λ=h√2m×K.E. λ=h√2m×h(v−v0)