Dear student,
Find the answer to your query as under:
considering latent heat of fusion to be = L = 333.55 kJ/kg = 333550 J/ kg
The mass of the ice that gets converted to water = m/60
now,
the energy needed for the ice to melt = mass × latent heat of fusion = (m/60) × 333550 J ---- (1)
now,
the potential energy stored in the ice when it falls from the height 'h' = mgh
now,
only 1/5 th of it gets converted to heat.
Thus, total heat energy available = 1/5 mgh ----- (2)
for the conversion of ice to water to take place eq (1) = eq (2)
or,
taking g = 10 m/s2
1/5 mgh = m/ 60 × 333550
h = 277.95 m
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Regards
Satyendra Singh