MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

History of Snell's Law

When a point ...

Question

When a point source is inside at a depth H in water (refractive index Image not present), the fraction of light coming out of the water is 'a'. When source is placed at depth '2H', fraction of light escaped from water is 'b'. Then find relation between a and b.

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

Q. A bright point source of light is under water at a depth 12 cm. An observer's eye is at a height 12 cm above the surface of water. The distance of the image of the point source from the eye of the observer is (take refractive index of water as 4/3)

Q. A point source of light is placed at a depth of h below the surface of water of refractive index

μ

. A floating opaque disc is placed on the surface of water so that light from the source is not visible from the surface. The minimum diameter of the disc is

A point source is placed at a depth h below the surface of water (refractive index $= μ$ ).

(a) Show that light escapes through a circular area on the water surface with its centre directly above the point source.

(b) Find the angle subtended by a radius of the area on the source.

Q. A small bulb is placed at the bottom of a tank containing water to a depth of 80 cm.what is the area of the surface of water through which light from the bulb can emerge out? Refractive index of water is 1.33. Consider the bulb to be a point source.

Q. A point source is at a depth of 1 m from the water surface. The diameter of the circle of light rays on water surface refracted into the air will be (refractive index of water is

\frac{4}{3}

)

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Introduction to Snell's Law

PHYSICS

Watch in App

explore_more_icon

Explore more

History of Snell's Law

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon