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Question

When a point source is kept at a distance d from the cathode plate, the stopping potential was found to be Vs. If the distance is now reduced to half of the original, the change in stopping potential is,

A
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B

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C

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D
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Solution

The correct option is A 0 %
Stopping potential is, Vs=Eϕ0, where E and ϕ0, both are in eV.

As the distance between source and cathode plate is changed, the intensity of incident light changes. As the stopping potential does not depend on intensity, so the stopping potential is also independent of the distance of the source from the cathode plate.

Hence, (A) is the correct answer.
Why this question?
Concept: distance of source from the cathode plate determines Intensity of radiation falling on it, whereas, stopping potential is independent of intensity of radiation.

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