When a point source of light is at a distance of one meter from a photo cell, the cut off voltage is found to be $V$ . If the same source is placed at $2 m$ distance from photo cell, the cut off voltage will be -

V

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\frac{V}{2}

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\frac{V}{4}

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\frac{V}{\sqrt{2}}

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Solution

The correct option is A $V$
When the distance of the source from the photocell is increased, it will not effect cutoff voltage. It will remain V. By increasing distance intensity decreases, cut off voltage does not depend on intensity.

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When a point source of light is at a distance of one meter from a photo cell, the cut off voltage is found to be V. If the same source is placed at 2 m distance from photo cell, the cut off voltage will be -

The correct option is A VWhen the distance of the source from the photocell is increased, it will not effect cutoff voltage. It will remain V. By increasing distance intensity decreases, cut off voltage does not depend on intensity.

When a point source of light is at a distance of one meter from a photo cell, the cut off voltage is found to be $V$ . If the same source is placed at $2 m$ distance from photo cell, the cut off voltage will be -

The correct option is A $V$
When the distance of the source from the photocell is increased, it will not effect cutoff voltage. It will remain V. By increasing distance intensity decreases, cut off voltage does not depend on intensity.