When a point source of light is at a distance of one metre from a photo cell, the cut off voltage is found to be V. If the same source is placed at 2 m distance from photo cell, the cut off voltage will be

$V$

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$\frac{V}{2}$

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$\frac{V}{4}$

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$\frac{V}{\sqrt{2}}$

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Solution

The correct option is A
$V$

By changing distance of source, photoelectric current changes. But there is no change in stopping potential.

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When a point source of light is at a distance of one metre from a photo cell, the cut off voltage is found to be V. If the same source is placed at 2 m distance from photo cell, the cut off voltage will be

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When a point source of light is at a distance of one metre from a photo cell, the cut off voltage is found to be V. If the same source is placed at 2 m distance from photo cell, the cut off voltage will be

The correct option is A V By changing distance of source, photoelectric current changes. But there is no change in stopping potential.

The correct option is A
$V$

By changing distance of source, photoelectric current changes. But there is no change in stopping potential.