When a poly atomic gas undergoes an adiabatic process, its temperature and volume are related by the equation $T V^{n}$ =constant, the value of n will be

1.33

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0.33

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2.33

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Solution

The correct option is A 1.33

When a poly atomic gas undergoes as a diabetic process than its temp.and volume relative as $T V^{n}$ = constant.
for poly atomic :- $η = 1 + 2 / f = 1.33$
$∴$ option $A$ is correct.

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When a poly atomic gas undergoes an adiabatic process, its temperature and volume are related by the equationTVn =constant, the value of n will be

The correct option is A 1.33When a poly atomic gas undergoes as a diabetic process than its temp.and volume relative as TVn = constant.for poly atomic :- η=1+2/f=1.33 ∴ option A is correct.

When a poly atomic gas undergoes an adiabatic process, its temperature and volume are related by the equation $T V^{n}$ =constant, the value of n will be

The correct option is A 1.33

When a poly atomic gas undergoes as a diabetic process than its temp.and volume relative as $T V^{n}$ = constant.
for poly atomic :- $η = 1 + 2 / f = 1.33$
$∴$ option $A$ is correct.