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Question

When a polynomial p(x) is divided by x−2, the remainder is 7. When p(x) is divided by x−3, the remainder is 9. If r(x) is the remainder when p(x) is divided by (x−2)(x−3), then the value of r(−1) is

A
0
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B
1
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C
2
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D
4
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Solution

The correct option is B 1
Given that p(2)=7 & p(3)=9
Let p(x)=(x2)(x3)g(x)+r(x)
Since the degree of the remainder is always less than the degree of divisor, we get
r(x)=Ax+B

2A+B=7 and 3A+B=9
A=2 and B=3
r(x)=2x+3
r(1)=1





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