When a polynomial p(x) is divided by x−2, the remainder is 7. When p(x) is divided by x−3, the remainder is 9. If r(x) is the remainder when p(x) is divided by (x−2)(x−3), then the value of r(−1) is
A
0
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B
1
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C
2
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D
4
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Solution
The correct option is B1 Given that p(2)=7&p(3)=9 Let p(x)=(x−2)(x−3)g(x)+r(x) Since the degree of the remainder is always less than the degree of divisor, we get r(x)=Ax+B
⇒2A+B=7 and 3A+B=9 ⇒A=2 and B=3 ∴r(x)=2x+3 ⇒r(−1)=1